If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ is approximately a normal distribution

Yes we can conclude.

Step-by-step explanation:

The sampling distribution of can be approximated as a Normal Distribution only if:

np and nq are both equal to or greater than 10. i.e.

Both of these conditions must be met in order to approximate the sampling distribution of as Normal Distribution.

From the given data:

n = 50

p = 0.80

q = 1 - p = 1 - 0.80 = 0.20

np = 50(0.80) = 40

nq = 50(0.20) = 10

This  means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i