Mathematics, 05.09.2019 07:20, masie03

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative startfraction 2 over 5 endfraction left-parenthesis x minus 10 right-parenthesis.. what is the standard form of the equation for this line?
2x – 5y = –15
2x – 5y = –17
2x + 5y = –15
2x + 5y = –17

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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus...