You have $4.10 in nickels, dimes, and quarters. if you have twice as many dimes as quarters, and five more nickels than dimes, how many coins of each type do you have?

For this case, the first thing to do is define variables.

We have then:

We write now the system of equations:

Then rewriting the equations we have:

Then, substituting values we have:

Finally:

19 nickels

14 dimes

7 quarters

check the picture below.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length