Question 1. choose the point-slope form of the equation below that represents the line that passes through the points (−6, 4) and (2, 0). a) y − 4 = −one half(x + 6) b) y − 4 = 2(x + 6) c) y + 6 = −one half(x − 4) d) y + 6 = 2(x − 4) question 2 (multiple choice worth 2 points) given the equation y − 3 = one half(x + 6) in point-slope form, identify the equation of the same line in standard form. a) x − 2y = −12 b) y = one halfx c) y = one halfx + 6 d) y = one halfx + 9

First question: C) y + 6 = -1/2 ( x + 6)

Second question A) x - 2y = -12

Step-by-step explanation:

Question 1

First we calculate the slope:

m = (0-4)/(2+6) = (-4)/(8) = -1/2

Then we substitute in the formula

(y+6) = -1/2 (x+6)

Question 2

y - 3 = 1/2(x+6)

2(y-3) = x+6

2y -6 = x + 6

x - 2y = -12

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

step-by-step explanation:

because it just is