Tanya bought five adult tickets and one children's tickets to a movie for $37.10.li bought three adult tickets and five children's tickets for $38.10. find the cost of one adult ticket and the cost of one children's ticket.

Step-by-step explanation:

Let a and c represent the costs of 1 adult and 1 children's ticket, respectively. Then the two purchases can be written as ...

  5a +c = 37.10

  3a +5c = 38.10

Solving this system of equations will give the ticket prices.

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Subtracting the second equation from 5 times the first gives ...

  5(5a +c) -(3a +5c) = 5(37.10) -(38.10)

  22a = 147.40

  a = 6.70

The first equation is useful for finding the value of c:

  5(6.70) +c = 37.10

  c = 3.60 . . . . subtract 33.50

The cost of one adult ticket is $6.70; the cost of one children's ticket is $3.60.

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The two equations can also be solve quickly using a graphing program.

step-by-step explanation:

ask goog great chance of finding the solution there

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3