Gfind the equation for the plane containing the points (0, 0, 1), (1, 2, 3), (2, 4, 5), and (4, 8, 11). (b) consider the tangent plane to the surface z = x 2+xy−3y at the point (2, 3, 1). compute the angle of intersection between this plane and the plane from part (a

Step-by-step explanation:

Any 3 non collinear points would determine a unique plane. The four points given are:

P(0, 0, 1),Q (1, 2, 3), R(2, 4, 5), and S (4, 8, 11).

Direction ratios are listed below

PQ = 1,2,2

QR = 1,2,2

RS = 2,4,6

Hence we find that P,Q,R are collinear so let us select P,Q and S to determine the plane equation.

Hence we have plane equation

b) Given

Del w = (2x+y)i+(x-3)j-1k

At the point (2,3,1) normal would have direction ratios as

(7,-1,-1)

Hence tangent plane is

c) Angle of intersection would be the angle between normals

i.e. cos t = where t is the angle.

y=1/4x-4

step-by-step explanation: