Brad is working on a speed problem in physics class. the problem tells him that a girl runs from her house to the park 0.05 km away in 10 s. brad calculates that her speed is 0.005 m/s. is he correct? if not, explain the flaw or flaws in his problem solving process.

Brad is incorrect.

0.05 k m  =  0.05  ⋅  1000 m  =  50 m

s  =  d/ t

where  d  is distance in metres  (m) ,

and t is time in seconds.

and s is speed in meters per second m/s

d  =  50 m   and  t  =  10 s

50m/10s

s = 5 m/s

Brad did most everything correctly just that the number would need to be multiplied by  1000  since the unit  k m  was converted to  m .

table 3 represents a direct variation function. : )

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204