4.
solve the shape equation puzzle:
a+ a+ a+ b+ b=20
b+ a+ a=13

3A+2B=20

2A+B=13 ➡×(-2)➡-4A-2B=-26

3A+2B-4A-2B=20-26

-A=-6 ➡A=6

2(6)+B=13➡B=1

A = 6, B = 1.

Step-by-step explanation:

3A + 2B = 20

2A + B = 13          Multiply this by -2:

-4A - 2B = -26     Add this equation to the first equation:

-A = -6

A = 6.

and from the second equation:

2(6) + B = 13

B = 13 - 12 = 1.

you have 6 cupcakes

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2