How many half-lives of radon-222 have passed in 11.46 days? if 5.2 × 10−8 g of radon-222 remain in a sealed box after 11.46 days, how much was present in the box initially socratic. org

(i) Approximately 3 half lifes

(ii)

Step-by-step explanation:

(i) ∵ The half life of Radon-222 is approximately 3.8 days,

So, the number of half life in 11.46 days = ≈ 3

(ii) Since, the half life formula is,

Where,

= initial quantity,

t = number of periods

= half life of the quantity,

Given,

N =

t = 11.46 days,

wholesale price is the initial price before markup. retail price comes after the markup.

a price of 8 bucks that's marked up by 100%   is

formula: initial price + (percent markup in fraction/decimal)(initial price)

8+(1)(8)

8+8

16

retail price is $16.

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)