State the domain and range of the following relation by clicking on the answer to make the given answer correct.
{(x, y): y = x + 1, x is some even integer}
domain {x: x > = r}.
{x: x< =r}.
{x: x=r}.
{x: x (is not equal, sign) r}.
{x: x (belongs to r, sign) r}.
range: {y: y = r}.
{y: y (is not equal, sign) r}.
{y: y> =r}.
{y: y< =r}.
{y: y (belongs to r, sign) r}.
which ones are correct?
!
you so much in advance! : )

me! what did you put for this question?

step-by-step explanation:

i think the correct option is the second option.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it