The second side of the triangle deck is 4 feet longer than the shortest side. the third side of the deck is 4 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 76 feet, what are the lengths of the three sides?

Step-by-step explanation:

let s = the length of the shortest side

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Write an equation for each statement

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The second side of a triangular deck is 4 feet longer than the shortest side

(s+4) = the 2nd side

and a third side that is 4 feet shorter than twice the length of the shortest side.

(2s-4) = the 3rd side

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If the perimeter of the deck is 48 feet, what are the lengths of the three sides?

s + (s+4) + (2s-4) = 48

Combine like terms

s + s + 2s + 4 - 4 = 48

4s = 48

s = 48/4

s = 12 ft is the shortest side

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I'll let you find the 2nd and 3rd sides, ensure they add up to 48

squares, rhombus, rectangles