Mathematics, 30.08.2019 22:10, KeyesRaveen

He slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -x + 6. what is the point-stopetom
of the equation for this line?
y-3= 2 (x + )
y + 3 = 2 (x-8)
y + 8 = 2 (x-3)
–8= 2 (x + 3)

Answers: 2

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He slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -x + 6. what is the point-stopetomof the equation for this line? y-3= 2 (x + )y + 3 = 2 (x-8)y + 8 = 2 (x-3)–8= 2 (x + 3)

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He slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -x + 6. what is the point-stopetom
of the equation for this line?
y-3= 2 (x + )
y + 3 = 2 (x-8)
y + 8 = 2 (x-3)
–8= 2 (x + 3)