Question 3. find the following gcd and lcm: (3.a) gcd(343, 550), lcm(343, 550).|| (3.b) gcd(89, 110), lcm(89, 110). (3.c) gcd(870, 222), lcm(870, 222).

(3.a) GCD(343,550)=1

LCM(343, 550)=188650

(3.b) GCD(89, 110)=1

LCM(89, 110)=9790

(3.c) GCD(870, 222)=6

LCM(870, 222)=32190

Step-by-step explanation:

(3.a) GCD(343,550), LCM(343, 550).

343=7×7×7

550=5×5×2×11

GCD(343,550)=1

LCM(343,550)=7×7×7×5×5×2×11=188650

(3.b) GCD(89, 110), LCM(89, 110).

89=1×89

110=5×2×11

GCD(89, 110)=1

LCM(89, 110)=89×5×2×11=9790

(3.c) GCD(870, 222), LCM(870, 222).

870=2×3×5×29

222=2×3×37

GCD(870, 222)=2×3=6

LCM(870, 222)=2×3×5×29×37=32190