The ages of three sisters are consecutive integers. the sum of their ages is 72. calculate their ages.
write an equation, in standard form, that could be used to evaluate their ages.
what is the 1st child's age?
years old
what is the 2nd child's age?
years old
what is the 3rd child's age?
years old
remember: before you move on to the next question, make sure their ages add up to the total sum.

1st: 23 years old, 2nd: 24 years old, 3rd: 25 years old

Step-by-step explanation:

Let the ages a, b and c

a + b + c = 72

b = a + 1 (b is consecutive to a)

c = a + 2  (c is consecutive to b)

a + a + 1 + a + 2 = 72

3a +3 = 72

3a = 72-3 = 69

a = 69/3 = 23 years old, that is the 1st child's age

b = a + 1 = 24 years old, that is the 2nd child's age

c = a + 2 = 25 years old, that is the 3rd child's age

a + b + c= 23 + 24 + 25 = 72 years



x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead