Arectangular prism is removed from a triangular prism with a volume of 200 cubic units. the volume of the final figure is 180 cubic units.
what could be the dimensions of the prism that was removed?
4 by 2 by 5
3 by 1 by 8
2 by 1 by 7
2 by 2 by 5

  2 by 2 by 5

Step-by-step explanation:

The change in volume is 20 cubic units, so that must be the product of the dimensions of the cuboid removed.

a) 4×2×5 = 40 ≠ 20

b) 3×1×8 = 24 ≠ 20

c) 2×1×7 = 14 ≠ 20

d) 2×2×5 = 20 . . . . . this is the answer

2 by 2 by 5

Step-by-step explanation:

A rectangular prism is removed from a triangular prism with a volume of 200 cubic units. The volume of the final figure is 180 cubic units. Therefore, the dimensions of the prism that was removed could be 2 by 2 by 5.

200 - 180 = 20

2 by 2 by 5 = 20

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

56

step-by-step explanation: