The position function for a free-falling object is s(t) = -16t^2 + vt +5. a ball is thrown upward from the top of a 400-foot building with an initial velocity of 35 feet per second. at what time will the ball reach the ground (round answer to nearest hundredths)? o at 2.19 seconds at 0 seconds at 6.21 seconds at -4.02 seconds

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

Where,

= initial height of the object,

= initial velocity of the object,

Here,

Hence, the height of the ball after t seconds,

When s(t) = 0,

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

i think the answer is a p = 78

step-by-step explanation:

there are 6 sides of a hexagon, multiply 13 x 6