Find the rate of change of the function h(x) = 4x – 3 on the interval 0 ≤ x ≤ 1.

Rate of change of h ( x ) in given interval is 4

Step-by-step explanation:

[ Refer to the attachment ]

solving for critical points ( extreme points of interval )

Solving by Differentiation !!

Replace x with 0 and solve:

4(0) - 3 = 0-3 = -3

Replace x with 1 and solve:

4(1) - 3 = 4-3 = 1

Rate of change = change in Y over the change in x

Change in Y = 1 - -3 = 1+3 = 4

Change in x = 1-0 = 1

Rate of change = 4/1 = 4

4x and 6y

im not sure though

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step-by-step explanation:

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