You drive 6.0 km at 50 km/h and then another 6.0 km at 90 km/h. your average speed over the 12 km drive will be

64.2857 km/h

Step-by-step explanation:

Time taken to drive the first 6.0 km in hours = 6/50

Time take to drive another 6.0 km in hours = 6/90

Total time taken to drive 12 km in hours = (6/50) + (6/90)

= 6(50+90)/50x90

= 6x140/50x90

= 840/4500

The average speed over the 12 km is therefore 12 divided by 840/4500

= (12 x4500)/840

= 64.2857 km/h

Step-by-step explanation:

hello

the  speed is the relation between a distance traveled and the time used for it and it is given by the equation

Now, the average speed will be

Step 1

I drive 6.0 km at 50 km/h

from (1) it is possible to isolate t

Let

Step 2

then I drive 6.0 km at 90 km/h

Step 3

FInd total time and total displacement

step 4

finally, put these values into the equation(2)

V=64.29 km/h

Have a good day

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

addition

step-by-step explanation: