Helene claimed that the expected value when rolling a fair die was 3.5. steve said that wasn't possible. he said that the expected value was the most likely value in a single roll of the die, and since it wasn't possible for a die to turn up with a value of 3.5, the expected value couldn't possibly be 3.5. who is right

Helene is right

Step-by-step explanation:

Mathematically, the expected values is defined as the sum of all the possible outcomes that an event can have times the probality of the respective outcome:

x = ∑ p *i,

where x is the expected value, i represents every outcome that can occur, and p is the probability of said outcome.

Now, for the case of a dice, the expected value would be:

x = 1 * + 2 * + 3 * + 4 * + 5* + 6 * ,

as every outcome has the same chance of happenning. Solving we get that:

x= *(1 +2 +3 +4+5+6) = * 21 = 3.5

Helene is right.

the solution is 12x-6y

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