Find the quadratic equation for y=x^2+6x-7

x = -1 or x = 7

Step-by-step explanation:

From my understanding, y will be zero and you have to find the value of x.

Step 1: Middle term break

y = x² + 6x - 7

x² + 6x - 7 = 0

x² - 7x + x - 7 = 0

Step 2: Solve

x(x-7) + 1(x-7) = 0

(x+1) (x-7) = 0

x = -1 or x = 7

Therefore, the value of x is either -1 or 7.

!!

step-by-step explanation:

it's is b

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: