Water flows steadily through the variable area horizontal pipe shown in fig. p3.3. the centerline velocity is given by where x is in feet. viscous effects are neglected. (a) determine the pressure gradient, 1as a function of x2 needed to produce this flow. (b) if the pressure at section 112 is 50 psi, determine the pressure at 122 by 1i2 integration of the pressure gradient obtained in (a), 1ii2 application of the bernoulli equation. 0p0x, v 1011 x2 ˆi ft

answer: y=0 if that is what u r looking for

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west