The weights, in pounds, of the cats in an animal adoption center are normally distributed. if a random sample of cats is taken and the confidence interval is (7.9,12.7), what is the margin of error

2.4

Step-by-step explanation:

Given : The weights, in pounds, of the cats in an animal adoption center are normally distributed.

The confidence interval is (7.9,12.7)           (1)

Let be the sample mean of the weights, in pounds, of the cats in an animal adoption center.

We know that the confidence interval for population mean is given by :-

     (2)

From (1) and (2)

Subtracting (3) from (4), we get

Hence, the margin of error is E = 2.4

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )