Probabilities with possible states of nature: s1, s2, and s3. suppose that you are given a decision situation with three possible state of nature: s1, s2, and s3.the prior probabilities are p(s1) =.1, p(s2) = .6, and p(s3) = .3.with sample information i, p(i|s1) =.15, p(i|s2) = .2, and p(i|s3) = .1.compute p(s1|i)compute p(s2|i)compute p(s3|i)

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Step-by-step explanation:

Given information:

(1)

We need to find the value of P(s₁|I).

Therefore the value of P(s₁|I) is .

(2)

We need to find the value of P(s₂|I).

Therefore the value of P(s₂|I) is .

(3)

We need to find the value of P(s₃|I).

Therefore the value of P(s₃|I) is .

answer: no, but if it does it's a obvious pattern.

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: