The condition
pa
proves that abc and aefg are congruent by the sas criterion
no
...
![Mathematics](/tpl/images/cats/mat.png)
Mathematics, 27.08.2019 17:30, ringo12384
The condition
pa
proves that abc and aefg are congruent by the sas criterion
no
if ab ef, the
criterion for congruency is violated. in this situation, angle
|
angle g
reset
![answer](/tpl/images/cats/otvet.png)
Answers: 3
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