P(-3,-7)andq(3,-5) coordinate of the midpoint of the segment

(0,-6)

Step-by-step explanation:

(x₁,y₁)=(-3,-7)

(x₂,y₂)=(3,-5)

midpoint (x,y) =?

now,

x= (x₁+x₂)/2

 = (-3+3)/2

 =0/2 =0

y=(y₁+y₂)/2

 ={-7+(-5)} /2

 =(-7-5)/2

 =-12/2

 =-6

so,

midpoint (x,y)=(0,-6)

20

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form