Mathematics, 26.08.2019 23:30, iliketurtures

Correct answers only !
what is the check digit, d, for the visa number shown below?
4328 3103 2635 108d
a. 1
b. 3
c. 5
d. 7

Correct answers only ! what is the check digit, d, for the visa number shown below?

Answers: 1

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answered: cait8752

D.) 7

Step-by-step explanation:

To calculate the check digit, multiply every even-position digit (when counted from the right) in the number by two. If the result is a two digit number, then add these digits together to make a single digit (this is called the digital root):

Odd numbers: (1.)= 8 (3.)= 4 (5.)= 6 (7.)= 0 (9.)= 4 (11.)= 6 (13.)= 2 (15.)=(1 + 6)= 7

Even numbers: (2.)= 3 (4.)= 8 (6.)= 1 (8.)= 3 (10.)= 6 (12.)=5 (14.)=0

To this total, we then add every odd-position digit:

Odd = 37

Even = 26

This will result in a total:

37 + 26 = 63

The check-digit is what number needs to be added to this total to make the next multiple of 10:

Next multiple of 10 is 70.

70 - 63 = 7

Hope this helps : D

answered: jpsaad00

D. 7

Step-by-step explanation:

Divide the number into odd-numbered and even-numbered digits (starting counting digit number 1 from the right).

odd digits: d, 0, 5, 6, 3, 1, 8, 3 . . . . sum of 26+d

even digits: 8, 1, 3, 2, 0, 3, 2, 4 . . . sum of 23

Multiply the sum of even-numbered digits by 2, and add 1 for each even-numbered digit* that is 5 or greater: 23×2 +1 = 47

Add this to the sum of odd-numbered digits, and choose "d" so the result is a multiple of 10.

47 + (26+d) = 73+d

The next higher multiple of 10 is 80. For the total to be 80, d = 7.

* The actual algorithm is described as "for each product of a digit and 2 that is greater than 9, subtract 9 from the product." Doing that, the number added to the sum will be ...

for 5: 2×5 - 9 = 1for 6: 2×6 - 9 = 3for 7: 2×7 - 9 = 5for 8: 2×8 - 9 = 7for 9: 2×9 - 9 = 9

In each case, the number contributed to the sum is 1 more than twice the digit, mod 10.

answered: Guest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

answered: Guest

50- 250 is correct i did that one too

step-by-step explanation:

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