Mathematics, 25.08.2019 03:30, kevon9008
Which is equivalent to rootindex 3 startroot 8 endroot superscript one-fourth x?
Answers: 2
![(\sqrt[3]{8})^{\frac{1}{4}x }](/tpl/images/0195/4065/cf328.png)
, ![\implies \sqrt[3]{8}=2](/tpl/images/0195/4065/c2f63.png)
![(\sqrt[3]{8})^{\frac{1}{4}x}=(2)^{\frac{1}{4}x }](/tpl/images/0195/4065/f9000.png)
![(\sqrt[3]{8})^{\frac{1}{4}x}=(2^\frac{1}{4})^x](/tpl/images/0195/4065/f9d4a.png)
![a^{\frac{1}{n} }=\sqrt[n]{a}](/tpl/images/0195/4065/a3a2d.png)
![(\sqrt[3]{8})^{\frac{1}{4}x}=(\sqrt[4]{2})^x }](/tpl/images/0195/4065/89e38.png)
![(\sqrt[3]{8})^{\frac{1}{4}x}](/tpl/images/0195/4065/04a13.png)
is ![(\sqrt[4]{2})^{x}](/tpl/images/0195/4065/df9ec.png)
and this can be determined by using the arithmetic operations.![=(\sqrt[3]{8})^{\frac{1}{4}x}](/tpl/images/0195/4065/a7416.png)
in the above expression.![=(\sqrt[3]{2^3})^{\frac{1}{4}x}](/tpl/images/0195/4065/71c15.png)
![\sqrt[3] {2^3 }](/tpl/images/0195/4065/6f58b.png)
becomes 2 in the above expression.
![=(\sqrt[4]{2})^{x}](/tpl/images/0195/4065/78305.png)
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Which is equivalent to rootindex 3 startroot 8 endroot superscript one-fourth x?...
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