8. find the midpoint
of the base xy in axyz.

Coordinates of the midpoint...(2;1/2)

Step-by-step explanation:

Coordinates of X(5;2) and of Y(-1;-1)

Midpoint = [ (add x coordinates of the two points)÷ 2 ; (add y coordinates of the two points) ÷ 2 ]

Mid point = [(5-1)/2 ; (2-1)/2]

Midpoint = [ 4/2 ; 1/2 ]

;Midpoint.coordinates = (2;1/2)

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation: