What is the solution to the system of equation
-2x+6y=-38
3x-4y=32

x= 4

y= -5

Step-by-step explanation:

-2x+6y=-38    equation 1

3x-4y=32     equation 2

using equation 1 we have:

-2x+6y=-38  

6y +38 = 2x

3y + 19 = x   equation 3

using equation 3 in equation 2 we have:

3(3y + 19) - 4y = 32

9y + 57 -4y =32

5y = 32 -57

5y = -25

y= -25/5

y = -5

so we have:

3y + 19 = x  

3(-5) +19 = x

x= 4

solution set of the system of equations is (4, -5)

Step-by-step explanation:

System of the equations is given as

-2x + 6y = -38

By dividing this equation by 2

-x + 3y = - 19 (1)

3x - 4y = 32 (2)

Now we multiply equation (1) by 3 and add it to equation (2)

3(-x + 3y) + (3x - 4y) = 3(-19) + 32

-3x + 9y + 3x - 4y = -57 + 32

5y = -25

y = -5

Now we put y = -5 in equation (1)

-x + 3(-5) = -19

-x - 15 = -19

-x = 15 - 19

-x = -4

x = 4

Therefore, solution set of the system of equations is (4, -5)

answer: i don't understand it

step-by-step explanation: sorry