There’s a picture so i don’t have to type out the question

The correct option is: Both -5 and 1 are true solutions

Step-by-step explanation:

The given expression is:

√c^2+2c-4=√1-2c

By squaring both sides we get:

(√c^2+2c-4)^2=(√1-2c)^2

c^2+2c-4=1-2c

Move all the values to the L.H.S

c^2+2c-4-1+2c=0

c^2+4c-5=0

Now we will perform factorization:

c^2+5c-c-5=0

c(c+5)-1 (c+5)=0

(c+5)(c-1)=0

c+5 = 0   , c-1=0

c= 0-5    , c=0+1

c= -5 , c=1

Thus the correct option is Both -5 and 1 are true solutions