![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-2}[x-\stackrel{x_1}{(-2)}] \\\\\\ y=-2(x+2)\implies y=-2x-4](/tpl/images/0189/8352/9ae30.png)
Choose the equation that represents the graph.
graph of a line passing through points negative...
Mathematics, 23.08.2019 03:30, mbede002
Choose the equation that represents the graph.
graph of a line passing through points negative 2 comma 0 and 0 comma negative 4
y = −2x − 4
y = 2x + 4
y = −2x + 4
y = 2x − 4
Answers: 2
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