An article in the washington post on march 16, 1993 stated that nearly 45 percent of all americans have brown eyes. a random sample of n=82 c of i students found 30 with brown eyes. we test h0: p=.45 ha: p≠.45 (a) what is the z-statistic for this test? (b) what is the p-value of the test?

The z-statistic for this test is -1.547 and P-value of the test is  0.0618

Step-by-step explanation:

An article in the Washington Post on March 16, 1993 stated that nearly 45 percent of all Americans have brown eyes.

We are given that  A random sample of n=82 C of I students found 30 with brown eyes.

n = 82

x = 30

Now to find z statistic we will use one sample proportion test

Formula of test statistic =

                                      =

                                      =

So,  the z-statistic for this test is -1.547

Now refer the z table for p value .

p value = 0.0618

The P-value of the test is  0.0618

Hence the z-statistic for this test is -1.547 and P-value of the test is  0.0618

7

step-by-step explanation:

the answer would be 7