If the area (in square units) of the region under the curve of the function f(x)=5 , on the interval from x=a to x=8 is 20 square units, what is the value of a?
answers: 4, 5, 6, 7, or 8?

8.

Step-by-step explanation:

In the question it says x=a then says x=8 if you do the common process of elimination you can concluded the a=8.

a = 4

Step-by-step explanation:

The function y = f(x) = 5 is simply a horizontal straight line

the interval x=a and x= 8 represent vertical straight lines that intersect x = a and x = 8.

Hence the area above the x-axis that is bound by f(x) on the top and x=a & x=8 on the sides is simply a rectangle with height = 5 and length = ( 8 - a ), and its area is given by

area = height x length = 5 (8-a)

we are given that the area = 20,

hence

area = 20 = 5(8-a)

(8-a) = 20/5

8-a = 4

-a = 4 - 8

-a = -4

a = 4

question is incomplete.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3