In an a. p,the sum of first ten terms is -150 and the sum of next 10 terms is -550.find the a. p

S10 = -150;
 the sum of next 10 terms = S20 - S10 => -550 = S20  + 150 => S20 = -700;
S10 = -150 => 2a1 + 9r = -30;
 S20 = -700 => 2a1 + 19r = -70;
Then 10r = -40 => r = -4 , and, 2a1 -36 = -30 => 2a1 = 6 => a1 = 3;

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