What is the least number that has 4 odd factors that are all the same? each factor is greater than 1 and can have only 1 itself as factors

I'm not quite sure what you mean.
the factors can't be 1.
the factors have to be odd.
they have to be the same.
offhand i would say 3*3*3*3 would be equal to 9*9 = 81.
the number 81 has 4 odd factors that are all the same.
can't be 1 because 1 doesn't counts as a factor.
a prime number has 2 factors.
1 and itself.
every number has a factor of 1 and itself.

1,2,3 is prime 4 is not prime  is i would say four sine its all the same it's kind of like 1x1x1x1= 1 

D. i think it is the savings