F(x) = x2 + 10
what is the average rate of chan
hange of f over the interval [-2, -1]?

The average rate of change is given by [f(b) - f(a)]/(b - a), where a and b represent the interval [a, b].

Let a = -2

Let b = -1

[(-1)^2 + 10 - ((-2)^2 + 10)]/(-1 -(-2))

[1 + 10 - (4 + 10)]/(-1 + 2)

[1 + 10 -4 -10]/(1)

[1 - 4]/(1)

-3/1

-3