40y^14/10y^8 simplify radicals and use properties of rational exponents

4y^6

Step-by-step explanation:

Take out the constants:

40y^14/10y^8

= 40/10 * y^14 / y^8

= 4 * y^(14-8)

= 4 * y^6

= 4y^6

Hope this helped you :3

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.