Suppose f(x)=x^3 find the graph of f(x+4)

  graph 1

Step-by-step explanation:

f(x+4) shifts the graph of f(x) left 4 units. The graph that shows y=x^3 shifted left 4 units is graph 1.

The point (0, f(0)) = (0, 0) is the point of inflection on the curve. In the function f(x+4), the value of x must be -4 in order to get a y-value of 0. That is, the point that was (0, f(0)) now is (-4, f(-4+4)) = (-4, f(0)). It has been moved 4 units to the left.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.