The electric field in an xy plane produced by a positively charged particle is 8.55(4.5 3.0 ) n/c at the point (4.2, 4.9) cm and 126 n/c at the point (2.2, 0) cm. what are the (a) x and (b) y coordinates of the particle

(a) x=-3.15cm

(b)y=0cm

Step-by-step explanation:

Locate the point (4.2,4.9) cm and draw the vector 4.5i+3.j with the origin at this point, the end of the vector is going to be in the point (8.7,7.9). With point (2.2,0), after searching, draw a line to the right to represent that the direction of the field is toward the positive x-axis.

Draw a line in each point in the opposite direction of the field in that point, the point where these lines intersect each other is the position of the particle.

Is the point (-3.15,0)cm

(a) x=-3.15cm

(b)y=0cm

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )