An airplane is flying at 35,000 feet above sea level airplane started to send a rate of 2500 ft./min. after five minutes how many feet above sea level is the airplane

22,500 feet

Step-by-step explanation:

Initial Height of the airplane = 35000 feet

Rate of descend = 2500 ft/min

This means for every minute the height of the plane is decreasing by 2500 feet.

We have to find how high above the sea level is the airplane after 5 minutes.

Since, in one minute the distance of plane is decreasing by 2500 feet, in 5 minutes the decrease in its distance would be = 2500 x 5 = 12,500 feet

Thus, after 5 minutes the height of airplane would have decreased by 12,500 feet. Since, the initial height of airplane was 35,000 feet, the new height after 5 minutes would be:

Height after 5 minutes = 35000 - 125000 = 22,500 feet

After 5 minutes, airplane is 22,500 feet above the sea level

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.