Hurry strangers i really need ! a paper manufacturer is evaluating their packing procedures. currently, they package twelve reams of paper in a box—in three stacks of four reams. however, their company has been getting complaints from the retail stores that the box is too large and heavy for the average consumer to carry by their self. so, they have decided to reduce the weight of each box by ten pounds. you have been asked to explore the different packing options based on the new weight condition and present your recommendation to the ceo of the paper company.
identify three unique ways to package the paper given the new weight condition. include both the dimensions of the new boxes, as well as a verbal description of how the reams will be packaged. you may include sketches if you wish.

well...i thinks that 3 stacks will not work as it wont be a symmetric arrangement as 1 will be left out. So, 2 stacks of 5 each would be easy to carry. but the stacks should be placed in such a way that the lengths are parallel to each other and not in-line which would increase the length making it comparatively longer. its easier to hold a (2*8.5,11,2*5=17,11,17)compact box.

Step-by-step explanation:

And To reduce the weight by 10 lbs you need to remove two reams of paper, leaving you with 10 reams. The only way to fit these into a cuboid would be 5 stacks of 2, 2 stacks of 5, 1 stack of 10 or 10 stacks of 1. You need to figure out the dimensions of paper arranged like that then work out the surface area. Obviously 1 x 10 or 10 x 1 will be stupid because the box would be awkward to carry, so the correct answer will be whichever of the other two gives you the least surface area (and therefore requires the least packaging). I guess you also need to consider the relative orientations of the stacks - long end to long end or short end to short end.

answer: 1 and 3

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet