What is the center of a circle represented by the equation (x−5)2+(y+6)2=42? (−6,5) (−5,6) (5,−6) (6,−5)

(5,-6)

Step-by-step explanation:

Recall that the equation for a circle is given as:

(x – h)² + (y – k)² = r²

where, the center is represented by point (h,k) and r is the radius.

IF we compare this to our given equation:

(x−5)² + (y+6)² = 42

( x−5 )²+( y-(-6) )² = 42

we see that h = 5 and k = -6

hence the center is located at (5,-6)

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere