What is the solution to 3x^2-2+4=0
explain answer. i'm taking a practice test and don't understand this.

There are no real solutions

Step-by-step explanation:

Recall that for a quadratic equation in the form:

ax² + bx + c = 0

using the quadratic formula, that the discriminant of the formula is given by the following expression

Discriminant = b² - 4ac

If b² - 4ac < 0 > No real roots

If b² - 4ac > 0 > Two real roots

If b² - 4ac = 0 > One real roots

In our case, a = 3, b = -2 and c = 4

b² - 4ac = (-2)² - 4(3)(3) = 4 - 36 = -32 (which is <0)

Hence there are no real roots.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.