Afreezer has a temperature of 14 degrees fahrenheit. an ice-cube tray full of water is placed in the freezer. the function f(t)=ce(−kt)+14 represents the situation, where t is time in minutes, c is a constant, and k=0.045. after 15 minutes the water has a temperature of 40 degrees. what was the initial temperature of the water? round your answer to the nearest degree, and do not include units

  65

Step-by-step explanation:

You can use f(15) = 40 to solve for C, then find f(0), the initial temperature.

  40 = f(15)

  40 = Ce^(-0.045·15) +14 = .50916C +14

  26 = .50916C

  26/.50916 = C ≈ 51.065

Then f(0) is ...

  f(0) = 51.065·e^0 +14 = 65.065 ≈ 65

The initial temperature of the water was 65 degrees Fahrenheit.

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step-by-step explanation:

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