The weight of trucks traveling on a particular section of i-475 have a population mean of 15.8 tons and a population standard deviation of 4.2 tons. what is the probability a state highway inspector could select a sample of 49 trucks and find the sample mean to be 14.3 tons or less

0.0062

Step-by-step explanation:

Given : The weight of trucks traveling on a particular section of I-475 have a population mean of tons and a population standard deviation of tons.

Sample size : n=49

Let x be the random variable that represents the weight of trucks .

z-score :

For x= 14.3 tons

Now, the probability a state highway inspector could select a sample of 49 trucks and find the sample mean to be 14.3 tons or less will be :-

Hence, the probability a state highway inspector could select a sample of 49 trucks and find the sample mean to be 14.3 tons or less =0.0062

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

step-by-step explanation: