What is the sum of the probability of drawing a green marble and the probability of not drawing a green marble?

There are a total of 6 green marbles.

Along with 3 blue and 3 red.

There is a total of 12 marbles in the bag.

This would mean that you would have 6/12 chance of getting a green marble.

If you simplify this then it would be 1/2 chance of getting a green marble.

3/12 and 3/12 chance of getting a blue or red marble.

Therefore, there is 1/2 a chance of drawing a green marble and 1/2 a chance of not drawing a green marble.

Hope this helps! :3

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option