Refer to the accompanying data display that results from a sample of airport data speeds in mbps. complete parts (a) through (c) below. tinterval (13.046,22.15) x overbarequals17.598 sxequals16.01712719 nequals50 a. express the confidence interval in the format that uses the "less than" symbol. given that the original listed data use one decimal place, round the confidence interval limits accordingly. 13.05 mbpsless thanmuless than 22.15 mbps (round to two decimal places as needed.) b. identify the best point estimate of mu and the margin of error.

The confidence interval is the range of value of a sample that represents the population.

The given parameters are:

(a) Express the confidence interval in the required format

We have:

So, the required format is:

Where L and U are the lower and the upper intervals.

So, we have:

(b) Estimate of and the margin of error

The point estimate of the population is the sample mean

The margin of error (E) is then calculated as:

So, we have:

Hence, the margin of error is 4.522

Read more about confidence intervals at:

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(a)

(b) The best  point estimate of is the sample mean

The margin of error =  4.552

Step-by-step explanation:

Given : The confidence interval for the population mean =  (13.046 , 22.15)

Sample mean :

Standard deviation :

Sample size :

a. Let represents the population mean.

Then we can write the confidence interval for the population mean as :-

b. The best  point estimate of is the sample mean

Also, the lower limit of confidence interval can be written as

i.e.

Hence, the margin of error =  4.552

the number of the people going.

step-by-step explanation:

the cost to buy one movie ticket is $7. if the total cost for the movie is a function of how many people go, then the input is : the number of the people going.

the answer is 99.