Find the coordinates of k' after reflection of the triangle cross of parallel lines; first across the line x =-2 and then across the line x = 2. the coordinates for k is (-4,-2).

A reflection across an X axis, does not change the Y value.

So we will just look at the X value.

The original K point is on X = -4.

To reflect across X = -2, find the distance from K to the line , - 4 to - 2 is 2 units to the right.  This means the reflected point would need to be 2 units to the right of the line.

2 units to the right of - 2 would be 0 ( -2 + 2 = 0)

Now that point also gets reflected across a line at x = 2.

Like the first one, find the distance from the point to the line, 0 to 2 is 2 units, so now the new point needs to be 2 units to the right of the line.

2 + 2 = 4.

K' would be located at (4,-2)

2

step-by-step explanation:

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step-by-step explanation: