Acup of tea with initial temperature of i = 85c^(circ) is left in the room with a constant temperature a = 21^(circ). in one minute the tea cools down to 84c^(circ). what will be the temperature of the tea after an hour? when will the temperature of the tea be 22^(circ)?

Step-by-step explanation:

The temperature can be modeled by a decaying exponential function with an initial value of (85° -21°) = 64° and a vertical offset of 21°. The temperature T as a function of time t can be written as ...

  T(t) = 21 +64(63/64)^t . . . . where t is in minutes and T is in degrees

The ratio 63/64 is the fraction of the initial temperature difference that remains after 1 minute.

We are asked for two points on the curve described by this function:

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(a) T(60) = 21 +64(63/64)^60 ≈ 45.88

The temperature after 1 hour will be about 45.9 °C.

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(b) Solving for t, we get ...

  22 = 21 +64(63/64)^t . . . . fill in the value of T

  1 = 64(63/64)^t . . . . . . . . . subtract 21

  1/64 = (63/64)^t . . . . . . . . .divide by 64

  log(1/64) = t·log(63/64) . . . take the log

  log(1/64)/log(63/64) = t ≈ 264.08 . . . . divide by the coefficient of t

The temperature of the tea will be 22° after 264 minutes.

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step-by-step explanation:

answer: the answer is 127 degrees