Which of the following does not characterize stratified random sampling? a. nonrandom sampling is used b. the population is divided into strata that are distinct c. the population is divided into strata that are mutually exclusive and exhaustive d. the population is divided into strata that are homogenous

Using sampling concepts, it is found that the statement which does not characterize stratified random sampling is:

A. Nonrandom sampling is used

In stratified random sampling, the population is divided into groups called strata, and then a number of members of each group is sampled, by random sampling.

A similar problem is given at link

A. Nonrandom sampling is used

Step-by-step explanation:

Nonrandom sampling is used does not characterize stratified random sampling. This means that, the people that provide the samples prepare for what they are going to give out and how it is going to contribute to their company.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!